Is there a standard value for (or method for obtaining) epsilon in Python? I need to compare floating point values and want to compare against the smallest possible difference.

In C++ there’s a function provided ** numeric_limits::epsilon( )** which gives the epsilon value for any given data type. Is there an equivalent in Python?

The information is available in `sys.float_info`

, which corresponds to float.h in C99.

```
>>> import sys
>>> sys.float_info.epsilon
2.220446049250313e-16
```

### Answer：

As strcat posted, there is `sys.float_info.epsilon`

.

But don’t forget the pitfalls of using it as an absolute error margin for floating point comparisons. E.g. for large numbers, rounding error could exceed epsilon.

If you think you need a refresher, the standard reference is David Goldberg’s What Every Computer Scientist Should Know About Floating-Point Arithmetic, or for a simpler review you can check out The Floating Point Guide.

### Answer：

Surprised nobody mentioned this here; I think many people would use numpy.finfo( type(variable) ).eps instead. Or `.resolution`

if it is to assess precision.

Note that `finfo`

is only for floating point types, and that it also works with Python’s own `float`

type (i.e. not restricted to numpy’s types). The equivalent for integer types is `iinfo`

, though it does not contain precision information (because, well, why would it?).

### Answer：

If you cannot find a function to do that, remember that the algorithm to calculate the machine precision is very easy (you can test with your favourite programming language).E.g, for python:

```
eps = 1.0
while eps + 1 > 1:
eps /= 2
eps *= 2
print("The machine precision is:", eps)
```

In my case, I got:

`The machine precision is: 2.220446049250313e-16`