PHP’s base64_encode is returning a different string to the linux base64 command.
Why is this?
PHP:
$ php
<?php
echo base64_encode('test');
?>
dGVzdA==
Linux base64:
$ echo 'test' | base64
dGVzdAo=
echo usually outputs a new line character at the end of the string, to suppress that use the -n switch:
$ echo -n 'test' | base64
dGVzdA==
Similarly for PHP:
$ php
<?php
echo base64_encode("test\n");
?>
dGVzdAo=
Answer：
open console in your browser, type atob('dGVzdAo='):
(source: gyazo.com)
You have extra character in your input. And that is 0x0A (LF).
Answer：
When doing an echo it gives me this:
MacPro:~ bardiir$ echo 'test'
test
MacPro:~ bardiir$
I’d guess you might have an included line-ending in the unix one as echo is probably appending a newline character even if you pipe it throuch to the base64 encode.
Answer：
The linux base64 has a new line at the end.
Answer：
It is because Unix version encodes also the end of line.
To receive similar effect in PHP you will have to do something like that:
echo base64_encode('test'.PHP_EOL);
which will output:
dGVzdAo=
See the proof here: ideone.com/HorVD
EDIT: As Charles mentioned, PHP_EOL is platform-specific, so to check the above on Windows you will have to replace it with Unix-like end of line symbol:
echo base64_encode("test\n");
Answer：
The same to above guys.
In mac os X, just test this :
$ echo 'test' | cat -e
test$
Or,
$ echo -n 'test' | cat -e
test
And,about the echo command, can see the tip: