java – Initialize arrays using ternary operator-ThrowExceptions

Exception or error:

i tried something like this:


boolean funkyBoolean = true;
int array[] = funkyBoolean ? {1,2,3} : {4,5,6};

But this code won’t even compile.
Is there any explanation for this? isn’t funkyBoolean ? {1,2,3} : {4,5,6} a valid expression?
thank’s in advance!

How to solve:

You can only use the {1, 2, 3} syntax in very limited situations, and this isn’t one of them. Try this:

int array[] = funkyBoolean ? new int[]{1,2,3} : new int[]{4,5,6};

By the way, good Java style is to write the declaration as:

int[] array = ...

EDIT: For the record, the reason that {1, 2, 3} is so restricted is that its type is ambiguous. In theory it could be an array of integers, longs, floats, etc. Besides, the Java grammar as defined by the JLS forbids it, so that is that.

Answer:

boolean funkyBoolean = true;
int[] array = funkyBoolean ? new int[]{1,2,3} : new int[]{4,5,6};

Answer:

An array initializer may be specified
in a declaration, or as part of an
array creation expression (§15.10), creating an array and providing some initial values

That’s what the Java Spec says (10.6). So the ‘short’ version (with the creation expression) is only allowed in declarations (int[] a = {1,2,3};), in all other cases you need a new int[]{1,2,3} construct, if you want to use the initializer.

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