Javascript Math Object Methods – negatives to zero-ThrowExceptions

Just do something like

value = value < 0 ? 0 : value;

or

if (value < 0) value = 0;

or

value = Math.max(0, value);

I suppose you could use Math.max().

var num = 90;
num = Math.max(0,num); // 90

var num = -90;
num = Math.max(0,num); // 0

If you want to be clever:

num = (num + Math.abs(num)) / 2;

However, Math.max or a conditional operator would be much more understandable.
Also, this has precision issues for large numbers.

Math.positive = function(num) {
  return Math.max(0, num);
}

// or 

Math.positive = function(num) {
  return num < 0 ? 0 : num;
}

x < 0 ? 0 : x does the job .

I don’t believe that such a function exists with the native Math object. You should write a script to fill in the function if you need to use it.

Remember the negative zero.

function isNegativeFails(n) {
    return n < 0;
}
function isNegative(n) {
    return ((n = +n) || 1 / n) < 0;
}
isNegativeFails(-0); // false
isNegative(-0); // true
Math.max(-0, 0); // 0
Math.min(-0, 0); // -0

Source: http://cwestblog.com/2014/02/25/javascript-testing-for-negative-zero/