jquery – Set selected radio from radio group with a value-ThrowExceptions

Exception or error:

Why am I struggling with this?

I have a value: 5

How do I check the radio button of group “mygroup” with the value of 5?

$("input[name=mygroup]").val(5); // doesn't work?
How to solve:

With the help of the attribute selector you can select the input element with the corresponding value. Then you have to set the attribute explicitly, using .attr:

var value = 5;
$("input[name=mygroup][value=" + value + "]").attr('checked', 'checked');

Since jQuery 1.6, you can also use the .prop method with a boolean value (this should be the preferred method):

$("input[name=mygroup][value=" + value + "]").prop('checked', true);

Remember you first need to remove checked attribute from any of radio buttons under one radio buttons group only then you will be able to add checked property / attribute to one of the radio button in that radio buttons group.

Code To Remove Checked Attribute from all radio buttons of one radio button group –

$('[name="radioSelectionName"]').removeAttr('checked');

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There is a better way of checking radios and checkbox; you have to pass an array of values to the val method instead of a raw value

Note: If you simply pass the value by itself (without being inside an array), that will result in all values of “mygroup” being set to the value.

$("input[name=mygroup]").val([5]);

Here is the jQuery doc that explains how it works: http://api.jquery.com/val/#val-value

And .val([...]) also works with form elements like <input type="checkbox">, <input type="radio">, and <option>s inside of a <select>.

The inputs and the options having a value that matches one of the elements of the array will be checked or selected, while those having a value that don’t match one of the elements of the array will be unchecked or unselected

Fiddle demonstrating this working: https://jsfiddle.net/92nekvp3/

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Try this:

$('input:radio[name="mygroup"][value="5"]').attr('checked',true);

JS Fiddle demo.

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$("input[name='mygroup'][value='5']").attr("checked", true);

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When you change attribute value like mentioned above the change event is not triggered so if needed for some reasons you can trigger it like so

$('input[name=video_radio][value="' + r.data.video_radio + '"]')
       .prop('checked', true)
       .trigger('change');

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$("input[name='RadioTest'][value='2']").prop('checked', true);

JS fiddle Demo

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Or you can just write value attribute to it:

$(':radio[value=<yourvalue>]').attr('checked',true);

This works for me.

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var key = "Name_radio";
var val = "value_radio";
var rdo = $('*[name="' + key + '"]');
if (rdo.attr('type') == "radio") {
 $.each(rdo, function (keyT, valT){
   if ((valT.value == $.trim(val)) && ($.trim(val) != '') && ($.trim(val) != null))

   {
     $('*[name="' + key + '"][value="' + (val) + '"]').prop('checked', true);
   }
  })
}

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Pure JavaScript version:

document.querySelector('input[name="myradio"][value="5"]').checked = true;

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$("input[name=mygroup]").val([5]);

Here is the jQuery doc that explains how it works: http://api.jquery.com/val/#val-value

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$('input[name="mygroup"]').val([5])

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