python – Convert bytes to int?-ThrowExceptions

Exception or error:

I’m currently working on an encryption/decryption program and I need to be able to convert bytes to an integer. I know that:

bytes([3]) = b'\x03'

Yet I cannot find out how to do the inverse. What am I doing terribly wrong?

How to solve:

Assuming you’re on at least 3.2, there’s a built in for this:

int.from_bytes( bytes, byteorder, *, signed=False )

The argument bytes must either be a bytes-like object or an iterable
producing bytes.

The byteorder argument determines the byte order used to represent the
integer. If byteorder is “big”, the most significant byte is at the
beginning of the byte array. If byteorder is “little”, the most
significant byte is at the end of the byte array. To request the
native byte order of the host system, use sys.byteorder as the byte
order value.

The signed argument indicates whether two’s complement is used to
represent the integer.

## Examples:
int.from_bytes(b'\x00\x01', "big")                         # 1
int.from_bytes(b'\x00\x01', "little")                      # 256

int.from_bytes(b'\x00\x10', byteorder='little')            # 4096
int.from_bytes(b'\xfc\x00', byteorder='big', signed=True)  #-1024

Answer:

int.from_bytes( bytes, byteorder, *, signed=False )

doesn’t work with me
I used function from this website, it works well

https://coderwall.com/p/x6xtxq/convert-bytes-to-int-or-int-to-bytes-in-python

def bytes_to_int(bytes):
    result = 0
    for b in bytes:
        result = result * 256 + int(b)
    return result

def int_to_bytes(value, length):
    result = []
    for i in range(0, length):
        result.append(value >> (i * 8) & 0xff)
    result.reverse()
    return result

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