android – methods in foreach and for loops in java-ThrowExceptions

Exception or error: My question is regarding optimization in java using the Android compiler. Will map.values() in the following be called every iteration, or will the Android compiler optimize it out. LinkedHashMap<String, Object> map; for (Object object : map.values()) { //do something with object } Likewise here is another example. will aList.size() be called every …

html – WHILE loops can't be used twice? PHP-ThrowExceptions

Exception or error: I am new to PHP , I hope someone can help me. I have a table which contains “id” , “img” , “link” and “desc” in mysql database . I want it to echo all out into something like this : <div id=”featured”> <a target=’_blank’ href=’link’><img src=’image link1′ title=’description’/></a> <a target=’_blank’ href=’link’><img …

Identify loops in java byte code-ThrowExceptions

Exception or error: I am trying to instrument java byte code. I want to recognize the entry and exit of a java loop, but I have found the identification of loops to be quite challenging. I have spent a good few hours looking at ASM and open source de-compilers (whom I thought must solve this …

Replace two nested for loops with java 8 API-ThrowExceptions

Exception or error: I have the following snippet and I wonder if and how it is possible to replace it with Streams/Java 8 API for (State state : states) { for (City city : cities) { if (state.containsPoint(city.getLocation())) { System.out.printf(“%30s is part of %-30s\n”, city.getName(), state.getName()); } } } How to solve: Will be something …

java – Break in nested for loops-ThrowExceptions

Exception or error: This question already has answers here: Closed 7 years ago. Possible Duplicate: How to Break from main/outer loop in a double/nested loop? I have the following situation: for(int i = 0; i < schiffe.length-1; i++){ if(schiffe[i].schaden){ schlepper.fliege(schiffe[i].x, schiffe[i].y, schiffe[i].z); schlepper.wirdAbgeschleppt = schiffe[i]; for(int k = 0; k < stationen.length-1; k++){ if(stationen[k].reparatur == …