unbuffered stdout in python (as in python -u) from within the program-ThrowExceptions

Exception or error:

Possible Duplicate:
Python output buffering

Is there any way to get the effect of running python -u from within my code? Failing that, can my program check if it is running in -u mode and exit with an error message if not? This is on linux (ubuntu 8.10 server)

How to solve:

The best I could come up with:

>>> import os
>>> import sys
>>> unbuffered = os.fdopen(sys.stdout.fileno(), 'w', 0)
>>> unbuffered.write('test')
test>>> 
>>> sys.stdout = unbuffered
>>> print 'test'
test

Tested on GNU/Linux. It seems it should work on Windows too. If I knew how to reopen sys.stdout, it would be much easier:

sys.stdout = open('???', 'w', 0)

References:
http://docs.python.org/library/stdtypes.html#file-objects
http://docs.python.org/library/functions.html#open
http://docs.python.org/library/os.html#file-object-creation

[Edit]

Note that it would be probably better to close sys.stdout before overwriting it.

Answer:

You could always pass the -u parameter in the shebang line:

#!/usr/bin/python -u

Answer:

You might use the fact that stderr is never buffered and try to redirect stdout to stderr:

import sys
#buffered output is here
doStuff()

oldStdout = sys.stdout
sys.stdout = sys.stderr
#unbuffered output from here on

doMoreStuff()
sys.stdout = oldStdout

#the output is buffered again
doEvenMoreStuff()

Answer:

Assuming you’re on Windows:

msvcrt.setmode(sys.stdout.fileno(), os.O_BINARY)

… and on Unix:

fl = fcntl.fcntl(sys.stdout.fileno(), fcntl.F_GETFL)
fl |= os.O_SYNC
fcntl.fcntl(sys.stdout.fileno(), fcntl.F_SETFL, fl)

(Unix copied in from commented solution, rather than linking.)

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